996 Turbo / GT2 Turbo discussion on previous model 2000-2005 Porsche 911 Twin Turbo and 911 GT2.

Help me reach 600 awhp, please

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Old May 2, 2010 | 11:45 AM
  #31  
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Originally Posted by MARKSKI@911tuning
Assuming all supporting mods are done( and that is the key) it runs like 18g with stock ICs and stock intake...
The hardpiping along with the direct to turbo short intake takes care of a lot of lag...

win/win situation. so the low cost is because of the switching of only the compressor side? I always thought that the difference in price between the two was considerable. I guess I was misinformed
 
Old May 2, 2010 | 12:00 PM
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Originally Posted by Prche951
win/win situation. so the low cost is because of the switching of only the compressor side? I always thought that the difference in price between the two was considerable. I guess I was misinformed
I have this 18g, 20g down for a long time... the price per HP you get when compared to other 650 rwhp type turbos is huge... not sure what you have been told...
mark
 
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Old May 2, 2010 | 03:07 PM
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Originally Posted by Mx3Speed
Aha! Like the VBox idea.. Looking for a V-Box now! However, I live at 5500' altitude. So I have lots of HP loss up here. I know with Turbo's, I don't lose as much power as N/A engines would, but wonder what % I am losing up here. Oh well, I'll get to PHX sometime and test it out also.
Assume Atmospheric press = 14.5
Atm press @ 5,500' = 12.0

%loss @ 1 bar = (29.0-26.5)/29.0*100% = 9.1% (intake pressure, not HP)
 
Old May 2, 2010 | 03:18 PM
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Originally Posted by TTdude
Assume Atmospheric press = 14.5
Atm press @ 5,500' = 12.0

%loss @ 1 bar = (29.0-26.5)/29.0*100% = 9.1% (intake pressure, not HP)
Does the boost control in the Porsche DME target gauge or absolute pressure? My 1bar flash often shows 1.2 on the gauge at 6000+ft
 
Old May 2, 2010 | 03:25 PM
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Absolute pressure but not very accurately. The point is that in order to get the same pressure at higher altitude the turbine will have spin faster, perhaps faster than is efficient. Larger turbo might be needed at higher altitude to maximize output.
 
Old May 2, 2010 | 03:28 PM
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Originally Posted by TTdude
Absolute pressure but not very accurately. The point is that in order to get the same pressure at higher altitude the turbine will have spin faster, perhaps faster than is efficient. Larger turbo might be needed at higher altitude to maximize output.
Thanks, you'll definitely move down in compressor efficiency trying to maintain boost and your IC efficiency is already down so a better compressor is win-win. Just curious what the DME was trying to do.
 
Old May 2, 2010 | 04:10 PM
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Originally Posted by TTdude
Assume Atmospheric press = 14.5
Atm press @ 5,500' = 12.0

%loss @ 1 bar = (29.0-26.5)/29.0*100% = 9.1% (intake pressure, not HP)

yup, this is pretty close to my calcs for 6000 ft. The higher the pressure of the turbos the less the loss you will see. So I calculated my loss using 1.2 bar at 6000ft. Cars running 2-3 bar like evo's will loose considerably less power at altitude. Still a 9% loss is noticeable when your talking 500+ hp.
 
Old May 2, 2010 | 04:15 PM
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I may be wrong but are you using millibars regarding 29.0? Isn't standard day (sea level, 15 c) 29.92 mb? It wouldn't change anything much. I just want to make sure I'm not thinking about something else.
 
Old May 2, 2010 | 04:24 PM
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Originally Posted by ReeknHavic
I may be wrong but are you using millibars regarding 29.0? Isn't standard day (sea level, 15 c) 29.92 mb? It wouldn't change anything much. I just want to make sure I'm not thinking about something else.
29.0 is the total pressure in psi (~14.5 psi atmospheric for an SAE day and another 14.5 for 1 bar of boost)
 
Old May 2, 2010 | 04:42 PM
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As I suspected I was confused .

Mb would be 1013 and 29.92. I'm with you now.

Edit: Sorry for the tangent. Now back to our scheduled thread.
 

Last edited by ReeknHavic; May 2, 2010 at 08:51 PM.
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